UVA 644 Immediate Decodability （字符处理）-白红宇

UVA 644 Immediate Decodability （字符处理）

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发布时间：2019-06-20

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An encoding of a set of symbols is said to be immediately decodable if no code for one symbol is the prefix of a code for another symbol. We will assume for this problem that all codes are in binary, that no two codes within a set of codes are the same, that each code has at least one bit and no more than ten bits, and that each set has at least two codes and no more than eight.

Examples: Assume an alphabet that has symbols {

A, B, C, D}

The following code is immediately decodable:

A:01 B:10 C:0010 D:0000

but this one is not:

A:01 B:10 C:010 D:0000 (Note that A is a prefix of C)

Write a program that accepts as input a series of groups of records from a data file. Each record in a group contains a collection of zeroes and ones representing a binary code for a different symbol. Each group is followed by a single separator record containing a single 9; the separator records are not part of the group. Each group is independent of other groups; the codes in one group are not related to codes in any other group (that is, each group is to be processed independently).

For each group, your program should determine whether the codes in that group are immediately decodable, and should print a single output line giving the group number and stating whether the group is, or is not, immediately decodable.

The Sample Input describes the examples above.

0110001000009011001000009

Set 1 is immediately decodableSet 2 is not immediately decodable

一个串不能是还有一个串的前缀。

#include
     
      #include
      
       #include
       
        #include
        
         #include
         typedef long long LL;using namespace std;#define REPF( i , a , b ) for ( int i = a ; i <= b ; ++ i )#define REP( i , n ) for ( int i = 0 ; i < n ; ++ i )#define CLEAR( a , x ) memset ( a , x , sizeof a )//map
          
           q;char str[1100][10],s[10];int main(){ int cas=1; std::ios::sync_with_stdio(false); while(cin>>str[0]) { int l=1; char *p; while(cin>>str[l]&&str[l++][0]!='9'); int flag=1; REP(i,l-1) { REP(j,l-1) { if(i==j) continue; p=strstr(str[i],str[j]); if((p-str[i])==0) { flag=0; break; } } } if(flag) printf("Set %d is immediately decodable\n",cas++); else printf("Set %d is not immediately decodable\n",cas++); } return 0;}

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